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Question: \(Zn^{2 +}(aq) + 2e \rightarrow Zn(s).\) This is....

Zn2+(aq)+2e→Zn(s).Zn^{2 +}(aq) + 2e \rightarrow Zn(s). This is.

A

Oxidation

B

Reduction

C

Redox reaction

D

None of these

Answer

Reduction

Explanation

Solution

Zn(aq)2++2e−→Zn(s)0\overset{2 +}{Zn_{(aq)}} + 2e^{-} \rightarrow \overset{0}{Zn_{(s)}} reduction.