Question

$Zn + {H_2}S{O_4}(dil) \to ZnS{O_4} + {H_2} \uparrow$
Above reaction is :
A.Decomposition reaction
B.Displacement reaction
C.Combination reaction
D.Synthesis reaction

Answer 1

In the given question we have to observe the process going in the reaction. We get that the hydrogen is displaced by the zinc in the product to obtain the zinc sulfate. This also liberates the hydrogen in the reaction as the byproduct. This is the classic case of the displacement reaction in which the element in the reactant side is displaced in the product side for the reaction.

Complete step by step answer:
In the given reaction we can observe the processes going through in order to get the right reaction.
Now we have to categorize the given options in order of the systematic definitions.
Option 1: The decomposition reaction is the reaction in which the given single reactant has been decomposed to get multiple products and by products.
Option 2: The displacement reaction is the reaction in which the given element in the reactant is displaced by another element in the product to get products and by products.
Option 3: The combination reaction is the reaction in which the given multiple reactants are reacted in order to get a single product.
Option 4: The synthesis reaction is the reaction in which the given reactant is synthesised by the reaction in order to get multiple products and by products.
Now in the given reaction the zinc displaces the hydrogen in the reaction product therefore it is a kind of displacement reaction.

Therefore the correct option is the option B, Displacement reaction.

Note: There are some of the things which governs the process of displacing the given element in the compound. To do that we have to take the reactants into account. For instance, when iron is added to a copper sulphate solution, it displaces the copper metal. $A{\text{ }} + {\text{ }}B - C{\text{ }} \to {\text{ }}A - C{\text{ }} + {\text{ }}B$ . The above equation exists when A is more reactive than B.