Question

z is a complex number satisfying |z – 3| £ 4 and |wz – 1 – w²| = a (where w is complex cube root of unity) then :

• A. 0 £ a £ 2
• B. 0 £ a £ 8
• C. 2 £ a £ 8
• D. 2 £ a £ 4

Answer 1

Answer: (B)

0 £ a £ 8

Answer 2

Sol.|wz –1– w²| = a

Ž |z + 1| = a

Ž |z –3 + 4| = a

Ž |z – 3| + 4 ³ a

Ž 0 £ a £ 8