Question
Question: \[z\]...
z
A
∣z+i∣=∣z−i∣
B
∣z−5∣
C
z=x+iy
D
(x−5)2+y2
Answer
(x−5)2+y2
Explanation
Solution
Let =tan−1[1/(1+3)3/(1+3)]=tan−13=3π
⇒ arg(−1+i3)=tan−1(−13)=120o
⇒ arg(2−i3+i+2+i3−i)=arg(56+5i+i2+6−5i+i2)and =arg(510)=0
θ −π.