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Physics Question on Youngs double slit experiment

Young’s modulus of elasticity π‘Œ is expressed in terms of three derived quantities, namely, the gravitational constant 𝐺, Planck’s constant β„Ž and the speed of light 𝑐, as π‘Œ = π‘π›Όβ„Žπ›½πΊπ›Ύ. Which of the following is the correct option?

A

𝛼 = 7, 𝛽 = βˆ’1, 𝛾 = βˆ’2

B

𝛼 = βˆ’7, 𝛽 = βˆ’1, 𝛾 = βˆ’2

C

𝛼 = 7, 𝛽 = βˆ’1, 𝛾 = 2

D

𝛼 = βˆ’7, 𝛽 = 1, 𝛾 = βˆ’2

Answer

𝛼 = 7, 𝛽 = βˆ’1, 𝛾 = βˆ’2

Explanation

Solution

The dimensions of Young's modulus of elasticity (π‘Œ) are [𝑀][𝐿]⁻¹[𝑇]⁻², where [𝑀] represents mass, [𝐿] represents length, and [𝑇] represents time.
Let's analyze the dimensions of each derived quantity:
The speed of light (𝑐) has dimensions [𝐿][𝑇]⁻¹.
Planck's constant (β„Ž) has dimensions [𝑀][𝐿]Β²[𝑇]⁻¹.
The gravitational constant (𝐺) has dimensions [𝑀]⁻¹[𝐿]Β³[𝑇]⁻².
Substituting the dimensions of 𝑐, β„Ž, and 𝐺 into the expression π‘Œ = π‘π›Όβ„Žπ›½πΊπ›Ύ, we have:
[𝑀][𝐿]⁻¹[𝑇]⁻² = ([𝐿][𝑇]⁻¹)Ξ±([𝑀][𝐿]Β²[𝑇]⁻¹)Ξ²([𝑀]⁻¹[𝐿]Β³[𝑇]⁻²)Ξ³.
By equating the dimensions on both sides of the equation, we can set up the following equations:
For mass dimension: 1 = 0 + Ξ² - Ξ³.
For length dimension: -1 = 1Ξ± + 2Ξ² + 3Ξ³.
For time dimension: -2 = -1Ξ± - Ξ² - 2Ξ³.
Solving these equations simultaneously will allow us to determine the values of 𝛼, 𝛽, and 𝛾.
Solving the equations, we find that 𝛼 = 7, 𝛽 = -1, and 𝛾 = -2.
Therefore, the correct option is (A) 𝛼 = 7, 𝛽 = -1, 𝛾 = -2.