Question

Young’s experiment is performed with light of wavelength 6000Å wherein 16 fringes occupy a certain region on the screen. If 24fringes occupy the same region with another light, of wavelength $\lambda,$ then $\lambda$is:

• A. 6000 Å
• B. 4500 Å
• C. 5000 Å
• D. 4000 Å

Answer 1

Answer: (D)

4000 Å

Answer 2

$n_{1}\lambda_{1} = n_{2}\lambda_{2}$

$\lambda_{2} = \frac{n_{1}}{n_{2}}\lambda_{1} = \frac{16 \times 6000Å}{24} = 4000Å$