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Question

Question: You have prepared a saturated solution of sugar. Is it possible to dissolve some more grams of sugar...

You have prepared a saturated solution of sugar. Is it possible to dissolve some more grams of sugar to this solution? Justify your stand.

Explanation

Solution

Hint : A solution containing the maximum amount of a solute in a given solvent at room temperature. The main factor which influences solubility is temperature. It has a direct effect on solubility.

Complete step by step solution :
There are three types of solutions-saturated, unsaturated and supersaturated solutions.
A solution which is capable of dissolving more solute at a given temperature than it already contains is called unsaturated solution.
Supersaturated solution is a solution that contains more dissolved substance than a saturated solution.
No more can be dissolved in saturated solution and there exists a dynamic equilibrium between the dissolved solute and undissolved solute.
Solubility depends upon temperature and pressure. Pressure is applied for only gases dissolved in liquids. A best example for this is carbonated soda. When we open the carbonated soda, the pressure in the bottle is released. Thus the gas is removed from the solution.
When temperature is increased, solubility increases, i.e. more solute can be dissolved in the solution.
Thus it is possible to add some more solute to a saturated solution by heating the solution. By increasing the temperature, solubility increases.
Additional information:
Solutions are the homogeneous mixtures of substances. The term homogeneous means that the components are uniformly distributed and form a single phase. Acid rain is a solution of oxides of sulfur in rain water.

Note : When we add 40g40{\text{g}} salt in 100mL100{\text{mL}}of water at 20C{20^ \circ }{\text{C}}, sodium and chloride ions leave the crystal surface and enter the solution. As sodium chloride continues to dissolve more ions enter into the solution and the rate at which they return to the crystalline state increases. At equilibrium, no more sodium chloride dissolves in the solution leaving some amount of salt at the bottom of the vessel.