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Question

Physics Question on thermal properties of matter

You are given two spheres of same material and radii 10cm10\,cm and 20cm20\, cm. They are heated to the same temperature. They are placed in the same environment. The ratio of their rates of cooling will be

A

1:02

B

2:01

C

1:04

D

4:01

Answer

2:01

Explanation

Solution

Intensity of radiations emitted will be same from both the spheres. Let it be II. Then heat emitted per second Q = 4pr2I4pr^2I . If Δθ1\Delta\,\theta_1, be the change in temperature, then Q=mCΔθ=(43)πr3ρcΔθi.eΔθ=3I/rpcQ = m C\Delta\theta = \left(\frac{4}{3}\right)\pi r^{3}\rho c \Delta\theta i.e \Delta\theta = 3I/rpc 4πr2I=(43)πr3ρcΔθ=3Irpc4\pi r^{2}I=\left(\frac{4}{3}\right)\pi r^{3}\rho c \Delta\theta = \frac{3I}{rpc} Δθ1Δθ2=r2r1=21\frac{\Delta\theta_{1}}{\Delta\theta_{2}}=\frac{r_{2}}{r_{1}}=\frac{2}{1}