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Question

Physics Question on Electromagnetic induction

You are given two resistances R1R_{1} and R2.R_{2} . By using them singly, in series and in parallel, you can obtain four resistances of 1.5Ω,2Ω,6Ω1.5\, \Omega, 2\, \Omega, 6\, \Omega and 8Ω8\, \Omega. The values of R1R_{1} and R2R_{2} are

A

1Ω,7Ω1\, \Omega ,\,7\, \Omega

B

1.5Ω,6.5Ω1.5\, \Omega,\, 6.5\, \Omega

C

3Ω,5Ω3\,\Omega,\,5\, \Omega

D

2Ω,6Ω2\,\Omega ,\,6\,\Omega

Answer

2Ω,6Ω2\,\Omega ,\,6\,\Omega

Explanation

Solution

Let R1+R2=8ΩR_{1}+ R_{2}=8\, \Omega ...(i)
and R1R2R1+R2=1.5Ω\frac{R_{1} R_{2}}{R_{1}+R_{2}}=1.5\, \Omega ...(ii)
By using Eqs. (i) and (ii)) we obtain
R1=6ΩR_{1}=6\, \Omega and R2=2ΩR_{2}=2\, \Omega