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Question: You are given two converging lenses of focal length \[1.25cm\] and \(5cm\) to design a compound micr...

You are given two converging lenses of focal length 1.25cm1.25cm and 5cm5cm to design a compound microscope. If it is desired to have a magnification of 3030, find out the separation between the objective and the eyepiece.

Explanation

Solution

An upright microscope that uses two lens sets (a compound lens system) to achieve a higher magnification than a stereomicroscope is a compound microscope. A compound microscope produces a two-dimensional view, while a three-dimensional view is given by a stereo microscope. Tiny samples not identifiable with the naked eye are seen with the compound microscopes. Usually these samples are mounted under the microscope on a slide.
Magnification of a compound microscope can be written as,
M=M0MeM = {M_0} {M_e}
Where the magnification of microscope is MM, M0{M_0} is the magnification due to objective and Me{M_e} is magnifying power by the eye piece

Complete step by step solution:
Magnification of a compound microscope is given by:
M=M0MeM = {M_0} {M_e}

Where the magnification of microscope is MM, M0{M_0} is the magnification due to objective and Me{M_e} is magnifying power by the eye piece

We know that,
M0=Lf0{M_0} = \dfrac{L}{{{f_0}}} and Me=25fe{M_e} = \dfrac{{25}}{{{f_e}}}
Where LL is the distance between objective and eyepiece, f0{f_0} is the focal length of the objective and fe{f_e} is the focal length of the eye piece.
Therefore, M=Lf0×25feM = \dfrac{L}{{{f_0}}} \times \dfrac{{25}}{{{f_e}}}
It is given that, f0=1.25cm{f_0} = 1.25cm, fe=5cm{f_e} = 5cm and M=30M = 30
We get,
30=L1.25×255\Rightarrow 30 = \dfrac{L}{{1.25}} \times \dfrac{{25}}{5}

L=7.5cm\Rightarrow L = 7.5cm

Therefore, the distance between the objective and eyepiece is 7.5cm7.5cm.

Note: With the aid of a compound microscope, two lenses can transcend the limits on resolution (and thus magnification power) imposed by the restrictions of the simple microscope. One of them has a small focal length and is positioned near the object under investigation. It is used to create a real picture in the middle of the front, eye or eye lens. The oculus forms a broader virtual image that the viewer can see. The compound microscope magnification strength is the combination of the lens magnification and the eyepiece magnification.