Question

Yash find out that ${{F}_{1}}$ and ${{F}_{2}}$ of symmetric convex lens experimentally then which of the conclusion will be true.

& A.{{F}_{1}}={{F}_{2}} \\\ & B.{{F}_{1}}>{{F}_{2}} \\\ & C.{{F}_{1}}<{{F}_{2}} \\\ & D.{{F}_{1}}\ne {{F}_{2}} \\\ \end{aligned}$$

Answer 1

A convex lens or a converging lens are defined as the lenses that are bulged at the centre. A convex lens includes two circular arcs. If the two arcs of a lens are having identical radius it is defined as a symmetric lens. This all will help you in answering this question.

Complete step by step answer:
${{F}_{1}}$ and ${{F}_{2}}$ of symmetric convex lenses are symmetric, all angles will be the same. ${{F}_{1}}$ and ${{F}_{2}}$ of the symmetric convex lens are divided into two equal parts so ${{F}_{1}}={{F}_{2}}$, so that it mainly have the equal focal length. When the ${{F}_{1}}$ is greater than ${{F}_{2}}$, the image will be farther away from the optic centre.
Therefore we can conclude that the focal length of each of the faces of the symmetric convex lens will be equivalent.

The answer has been given as option A.

Note:
One or both of the faces of the lens is part of a sphere, either concave or convex in nature. A lens is referred to as a convex lens if it is thicker at the centre than at the edges. If the edges are thicker than the middle part, then it is a concave lens. A double convex lens is a kind of lens which has focal points on both sides of the lens. The points at twice the focal length are helpful in locating objects and images. The focal length of a lens is defined as a measure of the strength of the system in order to converge or diverge the light. It is found to be the reciprocal of the optical power of the system.