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Question

Question: Y^2=8X a tangent is passing through this parabola then what is the tangent...

Y^2=8X a tangent is passing through this parabola then what is the tangent

Answer

Y = mX + 2/m

Explanation

Solution

The given parabola is Y2=8XY^2 = 8X.

Comparing this with the standard form of a parabola y2=4axy^2 = 4ax, we find that 4a=84a = 8, which implies a=2a = 2.

There are two common forms for the general equation of a tangent to a parabola:

  1. Tangent in terms of its slope (mm):

    The equation of a tangent to the parabola y2=4axy^2 = 4ax with slope mm is given by:

    y=mx+amy = mx + \frac{a}{m}

    Substituting a=2a = 2 and using variables XX and YY:

    Y=mX+2mY = mX + \frac{2}{m}

  2. Tangent at a point (X1,Y1)(X_1, Y_1) on the parabola:

    The equation of the tangent to the parabola Y2=8XY^2 = 8X at a point (X1,Y1)(X_1, Y_1) lying on the parabola is found by replacing Y2Y^2 with YY1Y Y_1 and XX with X+X12\frac{X+X_1}{2}:

    YY1=8(X+X12)Y Y_1 = 8 \left(\frac{X+X_1}{2}\right)

    YY1=4(X+X1)Y Y_1 = 4(X+X_1)

Given the general nature of the question "what is the tangent", the equation in terms of its slope is generally expected.