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Question

Question: y = log\sqrt{\frac{1+cos3x}{1+cos3x}}...

y = log\sqrt{\frac{1+cos3x}{1+cos3x}}

Answer

0

Explanation

Solution

Solution:

We are given

y=log1+cos3x1+cos3x.y=\log\sqrt{\frac{1+\cos3x}{1+\cos3x}}.

Since the numerator and denominator are identical,

1+cos3x1+cos3x=1.\frac{1+\cos3x}{1+\cos3x} = 1.

Thus,

1=1andy=log(1)=0.\sqrt{1} = 1 \quad \text{and} \quad y=\log(1)=0.

Since yy is a constant, its derivative is

dydx=0.\frac{dy}{dx}=0.

Explanation (minimal):

Simplify yy to get y=log1=0y=\log1=0. Therefore, dydx=0\frac{dy}{dx}=0.