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Question: y = \(f(x) = 2^{x(x - 1)}\) where t =\(f^{- 1}(x)\), then the number of points of discontinuities of...

y = f(x)=2x(x1)f(x) = 2^{x(x - 1)} where t =f1(x)f^{- 1}(x), then the number of points of discontinuities of y = f(x), x ∈ R is-

A

1

B

2

C

3

D

Infinite

Answer

3

Explanation

Solution

t = 1x1\frac { 1 } { x - 1 } is discontinuous at x = 1

y = is discontinuous at t = – 2 and t = 1

t = – 2, 1x1\frac { 1 } { x - 1 } = – 2 ⇒ x = 1/2

t = 1, 1x1\frac { 1 } { x - 1 } = 1 ⇒ x = 2

y = f(x) is discontinuous at three points 1, 12\frac { 1 } { 2 }, 2.