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Question

Question: \[xy = 1\]...

xy=1xy = 1

A

∴\therefore

B

3x2+4xy−3y2=3(x−y)(x+y+4)3x^{2} + 4xy - 3y^{2} = 3(x - y)(x + y + 4)

C

=3.(5+25−2−5−25+2)(5+25−2+5−25+2)+4= 3.\left( \frac{\sqrt{5} + \sqrt{2}}{\sqrt{5} - \sqrt{2}} - \frac{\sqrt{5} - \sqrt{2}}{\sqrt{5} + \sqrt{2}} \right)\left( \frac{\sqrt{5} + \sqrt{2}}{\sqrt{5} - \sqrt{2}} + \frac{\sqrt{5} - \sqrt{2}}{\sqrt{5} + \sqrt{2}} \right) + 4

D

None of these

Answer

3x2+4xy−3y2=3(x−y)(x+y+4)3x^{2} + 4xy - 3y^{2} = 3(x - y)(x + y + 4)

Explanation

Solution

⇒\Rightarrow.