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Question

Question: $x^{\log_a5}=\frac{1}{2}$...

xloga5=12x^{\log_a5}=\frac{1}{2}

Answer

The final boxed answer is incorrect. The correct solution is x=alog52x = a^{-\log_5 2}.

Explanation

Solution

The derivation correctly establishes logax=log52\log_a x = -\log_5 2. Converting this logarithmic form to its exponential form (logbM=N    M=bN\log_b M = N \iff M = b^N) yields x=alog52x = a^{-\log_5 2}. The user's final expression, a2log5a\frac{a}{2^{-\log_5a}}, simplifies to a1+log52a^{1+\log_5 2}, which is algebraically distinct from the correct solution.