Question

The value of current 'I' in the given current distribution is

• A. 2.2 A
• B. 0.2 A
• C. 1.9 A
• D. 1.5 A

Answer 1

Answer: (D)

1.5 A

Answer 2

Let the sum of currents entering the node be equal to the sum of currents leaving the node.

Incoming current = $1.2\text{ A} + 1.0\text{ A} = 2.2\text{ A}$

At the node, the outgoing currents are:

• $0.2\text{ A}$
• $0.1\text{ A}$
• The continuing branch which further splits into $I$ and $0.4\text{ A}$

Thus, the total outgoing current is:

$0.2 + 0.1 + (I + 0.4) = I + 0.7\text{ A}$

Setting the incoming and outgoing currents equal:

$2.2 = I + 0.7 \quad \Rightarrow \quad I = 2.2 - 0.7 = 1.5\text{ A}$