Xenon hexafluoride on partial hydrolysis produces compounds... | Chemistry | SolveeIt

Question

Xenon hexafluoride on partial hydrolysis produces compounds ?X? and ?Y?. Compounds ?X? and ?Y? and the oxidation state of Xe are respectively :

$XeO_2(+4)$ and $XeO_3(+6)$

$XeOF_4(+6)$ and $XeO_3(+6)$

$XeO_2F_2(+6)$ and $XeO_2(+4)$

$XeOF4(+6)$ and $XeO2F2(+6)$

Answer

$XeOF4(+6)$ and $XeO2F2(+6)$

Explanation

Solution

The reactions involved are as follows:

$XeF _{6}+ H _{2} O \rightarrow \underset{( X )}{\overset{+6}{Xe} OF _{4}}+2 HF$
$\underset{(X)}{XeOF _4}+ H _{2} O \rightarrow \underset{( Y )}{\overset{+6}{Xe} O _{2} F _{2}}+2 HF$

Chemistry Question on p -Block Elements

Solution