Question

$Xe{F_4}$ on partial hydrolysis produces ________.
A. $Xe{F_4}$
B. $Xe{F_5}$
C. $XeO{F_2}$
D. $Xe{O_3}$

Answer 1

In order to the question, first we will react $Xe{F_4}$ by adding ${H_2}O$ . In partial hydrolysis, the amount of water is limited. Hydrolysis is the process of adding water to a molecule for the purpose of breaking it into simpler compounds.

Complete step-by-step answer: $Xe{F_4}$ on partial hydrolysis produces Xenon Oxyfluorides $XeO{F_2}$ . This reaction can be symbolically given as:
$Xe{F_4} + {H_2}O \to XeO{F_2} + 2HF$
In the above reaction, $Xe{F_4}$ is added with the limited amount of water or ${H_2}O$ and gives the product as Xenon Oxydifluoride and Hydrogen Fluoride. This reaction is known as the partial reaction of $Xe{F_4}$ .Hydrolysis of other xenon fluorides ($Xe{F_2}$ and $Xe{F_4}$ ) apparently does result in some redox reactions, with some oxygen being oxidized and some xenon being reduced.

Hence, the correct option is (C.) $XeO{F_2}$ .

Note: The oxyfluorides of xenon namely xenon oxydifluoride, $XeO{F_2}$ and xenon oxytetrafluoride, $$$XeO{F_4}$are also obtained by the partial hydrolysis of$Xe{F_4}$and$Xe{F_6}$ respectively. The structure of xenon compounds can be explained on the basis of the VSEPR theory as well as the concept of hybridization.