Question
Question: \[xa^{x - 1} + c\]...
xax−1+c
A
∫cotx⥂6mudx
B
logcosx+c
C
logtanx+c
D
None of these
Answer
∫cotx⥂6mudx
Explanation
Solution
∫x1sinx6mudx=
−21cosx+c.
xax−1+c
∫cotx⥂6mudx
logcosx+c
logtanx+c
None of these
∫cotx⥂6mudx
∫x1sinx6mudx=
−21cosx+c.