QuestionReportMathematics Question on Linear Equationsx+y=3,x−y=0,x+y=\sqrt 3, x-y=0,x+y=3,x−y=0, then x=x=x=A3\sqrt 33B−3-\sqrt 3−3C32\dfrac {\sqrt 3}{2}23D−32\dfrac {-\sqrt 3}{2}2−3Answer32\dfrac {\sqrt 3}{2}23ExplanationSolutionThe correct option is (C): 32\dfrac {\sqrt 3}{2}23.