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Chemistry Question on p -Block Elements

X reacts with NaOH (aqueous solution) to form Y and H2H_2. Aqueous solution of Y is heated to 323- 333 K and on passing CO2 {CO_2} into it, Na2CO3 {Na_2CO_3} and Z were formed. When Z is heated to 1200∘C,Al2O31200^{\circ}C , { Al_2O_3} is formed. X, Y and Z respectively are

A

\ceAl,AlCl3,NaAlO2\ce{Al, AlCl_3, NaAlO_2}

B

\ceZn,Na2ZnO2,Al(OH)3\ce{Zn, Na_2ZnO_2, Al(OH)_3}

C

\ceAl,Al(OH)3,AlCl3\ce{Al, Al(OH)_3, AlCl_3}

D

\ceAl,NaAlO2,Al(OH)3\ce{Al, NaAlO_2, Al(OH)_3}

Answer

\ceAl,NaAlO2,Al(OH)3\ce{Al, NaAlO_2, Al(OH)_3}

Explanation

Solution

Answer (d) Al,NaAlO2,Al(OH)3 {Al, NaAlO_2, Al(OH)_3}