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Question

Mathematics Question on Relations and functions

xR:2x1x3+4x2+3xRx \in R : \frac{2x -1}{x^3 + 4x^2 + 3x} \in R Equals

A

R - {0}

B

R- {0,1,3}

C

R-{0, -1,-3}

D

R- 0,-1,-3,+ 12\frac{1}{2}

Answer

R-{0, -1,-3}

Explanation

Solution

Let A=xR:2x1x3+4x2+3x A = x \in R : \frac{2x -1}{x^3 + 4x^2 + 3x} Now , x3+4x2+3x=x(x2+4x+3)x^3 + 4x^2 + 3x = x(x^2 + 4x + 3) =x(x+3)(x+1) = x(x+ 3) (x + 1) A=R0,1,3A = R - \\{0, -1, -3\\}