Question

x g of Ag was dissolved in $HNO_3$ and the solution was treated with excess of NaCl when 2.87 g of AgCl was precipitated. The value of x is

• A. 1.08g
• B. 2.16g
• C. 2.70g
• D. 1.62g

Answer 1

Answer: (B)

2.16g

Answer 2

$143.5\,g\,Agcl$ contains $Ag=108\,g$ $2.87\,g\,Agcl$ contains $Ag=\frac{108\times2.87}{143.5}$ $=2.16\,g$