Question

$X Cl _{2}( excess )+Y Cl _{2} X Cl _{4}+Y \downarrow$ $Y O {->[{\Delta}][{>400^{\circ} C }]} \frac{1}{2} O _{2}+Y$ Ore of Y would be ,

• A. siderite
• B. malachite
• C. hornsilver
• D. cinnabar

Answer 1

Answer: (D)

cinnabar

Answer 2

$\underset{\left( xCl _{2} 2\right)}{ SnCl _{2}}+\underset{\left( y Cl _{-} 2\right)}{ HgCl _{2}} \longrightarrow \underset{\left( xCl _{-} 2\right)}{ SnCl _{4}}+\underset{( y )}{ Hg }$
$HgO \underset{>400^{\circ} C }{\longrightarrow} Hg \frac{1}{2} O _{2}$
So ore of $\gamma$ is $HgS$ i.e., Cinnabar.