Question

x²-3x+4=0 find real solution

Answer 1

No real solution

Answer 2

The given equation is $x^2 - 3x + 4 = 0$.

This is a quadratic equation of the form $ax^2 + bx + c = 0$, where $a=1$, $b=-3$, and $c=4$.

To find the nature of the solutions, we calculate the discriminant, $\Delta = b^2 - 4ac$.

$\Delta = (-3)^2 - 4(1)(4) = 9 - 16 = -7$.

Since the discriminant $\Delta < 0$, the quadratic equation has no real solutions. The solutions are complex.