Question

$(x -1) (x^2 - 5x + 7) < (x -,1),$ then $x$ belongs to

• A. $(1,2) \cup (3 , \infty)$
• B. $(- \infty ,1) \cup (2 , 3)$
• C. $(2, 3)$
• D. none of these

Answer 1

Answer: (B)

$(- \infty ,1) \cup (2 , 3)$

Answer 2

Given that, $(x-1)\left(x^{2}-5 x+7\right)