Question

Write the symbol with a charge of the radicals present and then write the formula of the following compounds:

Compound	Basic radical	Acidic radical	Formula
Sodium sulfate
Calcium phosphate
Copper (II) sulfide
Silver nitrate
Phosphorus pentoxide
Sodium zincate
Calcium chloride
Sodium nitrite
Potassium ferrocyanide
Potassium dichromate
Ammonium dichromate
Zinc sulfate
Magnesium bicarbonate
Nitrogen trichloride
Arsenic sulfide
Silicon dioxide
Potassium chromate

Answer 1

All the compounds given are salts, which are made up of different cations are anions, so, the positive part, i.e., the cation will be the basic radical while the negative part, i.e., the anion will be the acidic radical.

Complete step-by-step answer:
Sodium sulfate: Its formula is $N{{a}_{2}}S{{O}_{4}}$. The acidic radical will be $SO_{4}^{2-}$ and the basic radical will be $N{{a}^{+}}$.
Calcium phosphate: Its formula is $C{{a}_{3}}{{(P{{O}_{4}})}_{2}}$ . The acidic radical will be $PO_{4}^{3-}$ and the basic radical will be $C{{a}^{2+}}$ .
Copper (II) sulfide: Its formula is $CuS{{O}_{4}}$ . The acidic radical will be $SO_{4}^{2-}$ and the basic radical will be $C{{u}^{2+}}$.
Silver nitrate: Its formula is$AgN{{O}_{3}}$. The acidic radical will be $NO_{3}^{-}$ and the basic radical will be $A{{g}^{+}}$.
Phosphorus pentoxide: Its formula is ${{P}_{4}}{{O}_{10}}$. The acidic radical will be ${{O}^{2-}}$ and the basic radical will be ${{P}^{4+}}$.
Sodium zincate: Its formula is $N{{a}_{2}}Zn{{O}_{2}}$ . The acidic radical will be $Zn{{O}^{2-}}$ and the basic radical will be $N{{a}^{+}}$.
Calcium chloride: Its formula is $CaC{{l}_{2}}$ . The acidic radical will be $C{{l}^{-}}$ and the basic radical will be $C{{a}^{2+}}$.
Sodium nitrite: Its formula is$NaN{{O}_{2}}$ . The acidic radical will be $NO_{2}^{-}$ and the basic radical will be$N{{a}^{+}}$ .
Potassium ferrocyanide: Its formula is ${{K}_{4}}[Fe{{(CN)}_{6}}]$. The acidic radical will be ${{[Fe{{(CN)}_{6}}]}^{4-}}$ and the basic radical will be ${{K}^{+}}$.
Potassium dichromate: Its formula is${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ . The acidic radical will be $C{{r}_{2}}O_{7}^{2-}$ and the basic radical will be ${{K}^{+}}$.
Ammonium dichromate: Its formula is ${{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}$. The acidic radical will be $C{{r}_{2}}O_{7}^{2-}$ and the basic radical will be $NH_{4}^{+}$ .
Zinc sulfate: Its formula is $ZnS{{O}_{4}}$. The acidic radical will be $SO_{4}^{2-}$ and the basic radical will be $Z{{n}^{2+}}$.
Magnesium bicarbonate: Its formula is $Mg{{(HC{{O}_{3}})}_{2}}$ . The acidic radical will be $HCO_{3}^{-}$ and the basic radical will be $M{{g}^{2+}}$.
Nitrogen trichloride: Its formula is $NC{{l}_{3}}$ . The acidic radical will be $C{{l}^{-}}$ and the basic radical will be ${{N}^{3+}}$.
Arsenic sulfide: Its formula is $A{{s}_{2}}{{S}_{3}}$ . The acidic radical will be ${{S}^{2-}}$ and the basic radical will be$A{{s}^{3+}}$.
Silicon dioxide: Its formula is $Si{{O}_{2}}$ . The acidic radical will be ${{O}^{2-}}$ and the basic radical will be $S{{i}^{4+}}$.
Potassium chromate: Its formula is ${{K}_{2}}Cr{{O}_{4}}$. The acidic radical will be $CrO_{4}^{2-}$ and the basic radical will be ${{K}^{+}}$.

Compound	Basic radical	Acidic radical	Formula
Sodium sulfate	$N{{a}^{+}}$	$SO_{4}^{2-}$	$N{{a}_{2}}S{{O}_{4}}$
Calcium phosphate	$C{{a}^{2+}}$	$PO_{4}^{3-}$	$C{{a}_{3}}{{(P{{O}_{4}})}_{2}}$
Copper (II) sulfide	$C{{u}^{2+}}$	$SO_{4}^{2-}$	$CuS{{O}_{4}}$
Silver nitrate	$A{{g}^{+}}$	$NO_{3}^{-}$	$AgN{{O}_{3}}$
Phosphorus pentoxide	${{P}^{4+}}$	${{O}^{2-}}$	${{P}_{4}}{{O}_{10}}$
Sodium zincate	$N{{a}^{+}}$	$Zn{{O}^{2-}}$	$N{{a}_{2}}Zn{{O}_{2}}$
Calcium chloride	$C{{a}^{2+}}$	$C{{l}^{-}}$	$CaC{{l}_{2}}$
Sodium nitrite	$N{{a}^{+}}$	$NO_{2}^{-}$	$NaN{{O}_{2}}$
Potassium ferrocyanide	${{K}^{+}}$	${{[Fe{{(CN)}_{6}}]}^{4-}}$	${{K}_{4}}[Fe{{(CN)}_{6}}]$
Potassium dichromate	${{K}^{+}}$	$C{{r}_{2}}O_{7}^{2-}$	${{K}_{2}}C{{r}_{2}}{{O}_{7}}$
Ammonium dichromate	$NH_{4}^{+}$	$C{{r}_{2}}O_{7}^{2-}$	${{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}$
Zinc sulfate	$Z{{n}^{2+}}$	$SO_{4}^{2-}$	$ZnS{{O}_{4}}$
Magnesium bicarbonate	$M{{g}^{2+}}$	$HCO_{3}^{-}$	$Mg{{(HC{{O}_{3}})}_{2}}$
Nitrogen trichloride	${{N}^{3+}}$	$C{{l}^{-}}$	$NC{{l}_{3}}$
Arsenic sulfide	$A{{s}^{3+}}$	${{S}^{2-}}$	$A{{s}_{2}}{{S}_{3}}$
Silicon dioxide	$S{{i}^{4+}}$	${{O}^{2-}}$	$Si{{O}_{2}}$
Potassium chromate	${{K}^{+}}$	$CrO_{4}^{2-}$	${{K}_{2}}Cr{{O}_{4}}$

Note: Don’t get confused that the positive part will be the acidic radical and the negative part will be the basic radical. While writing the table, writing the valency is not necessary.