Question

Write the structure of (E)-Penta-1,3-diene.

Answer 1

n the given question description of the structure of $penta - 1,3diene$ has been asked. From the name we can understand that the compound includes a total five number of carbon atoms.

Complete Step by step answer:
A resolution for the description of a molecule showing cis-trans isomerism can be easily understood by E-Z Convention. The IUPAC preferred this method for describing the absolute Stereochemistry of a double bond Compound which has two, three or four Substituents contained in it. If more prior groups are attached on the opposite side of a double bond, then the structure will be known as E-isomer.

In the E-Z convention, we guise at the two substituents with the highest importance according to the CIP sequence rules. In both molecules we can name them as (a) and (b), where the both two have highest priority substituents. In molecule (a), these two are opposite each other, hence we say that they are in an E configuration, which stands for entgegen which means opposite in Germany. In molecule (b), these two are on the same side, hence we say that they are in an Z configuration, which stands for zusammen which means together in Germany.
Therefore, the Structure of $penta - 1,3di-ene$ is as follows –
$CH = CH - CH = CH - CH3$
So, this is the structure of (E)-penta -1,3-di-ene.

Note: In the system (E) is the higher priority groups are on opposite sides of the double bond whereas (Z) the higher priority groups are on the same side of the double bond. While drawing structure it should be kept in mind that the standard procedure must be followed for example starting from the longest chain and then for functional groups and all.