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Question: Write the structure of alkene formed by dehydrohalogenation of 1-bromo-1-methylcyclohexane with alco...

Write the structure of alkene formed by dehydrohalogenation of 1-bromo-1-methylcyclohexane with alcoholic KOHKOH.

Explanation

Solution

Hint : We have to draw the structure of 1bromo1methylcyclohexane1 - bromo - 1 - methylcyclohexane then only we can find the structure of alkene and understand the meaning of the word dehydrohalogenation.

Complete step by step solution :
Let's start with the formal definition, in dehydrohalogenation de stands for removal or elimination, hydro stands for hydrogen and halogen stands for halogen itself. So, dehydrohalogenation is the process of elimination of hydrogen and halogen. Therefore, we can understand that hydrogen bromide is being removed.
Now, we are given a substrate which is 1-Bromo-1-Methylcyclohexane whose molecular formula is C7H13BrC_7H_13Br. From the name of the substrate, we can see that the bromine, as well as the methyl group both, is present at the same position. So, the structure of the substrate is as follows
Now, in the presence of alcoholic KOH, bromine (halogen) and hydrogen from an adjacent carbon is being removed which leads to the formation of an alkene. The formation of alkene is shown below
Therefore we can conclude that the alkene formed is1methylcyclohex1ene1 - methylcyclohex - 1 - ene. This nomenclature is due to the presence of a methyl group at 1st position and a double bond present between the 1st and 2nd position. The other products of this reaction are KBr and H2OH_2O.

Additional information:
- Halogen groups represent all the atoms present in Group 17 of periodic table i.e. Fluorine (F), Chlorine (Cl), Bromine (Br), Iodine (I), and Astatine (At).Fluorine{\text{ }}\left( F \right),{\text{ }}Chlorine{\text{ }}\left( {Cl} \right),{\text{ }}Bromine{\text{ }}\left( {Br} \right),{\text{ }}Iodine{\text{ }}\left( I \right),{\text{ }}and{\text{ }}Astatine{\text{ }}\left( {At} \right).
- Alcoholic KOH is being used so that KOH acts as a base not as a nucleophile, if KOH acts as a nucleophile it will lead to the formation of alcohol rather than an alkene.

Note : We must understand that quicklime CaOCaO is used in daily household works and with the demand increasing in its production; industrial revolution is taking place with proper enumeration using it.