Question

Write the neutralization reaction between hydrochloric acid ($HCl$) and sodium hydroxide ($NaOH$), write the equation for this process?

Answer 1

We know that in science, neutralization is a chemical response wherein acid and a base respond quantitatively with one another. In a response in water, neutralization results in there being no overabundance of hydrogen or hydroxide particles present in the arrangement. The pH of the neutralization solution relies upon the corrosive strength of the reactants.

Complete answer:
It's anything but a double substitution response just as a balance response where particles are dislodged by beginning with two mixtures and finishing with two mixtures. The positive hydrogen particle on the Chlorine has been supplanted by a positive sodium particle on the Chlorine. While the Sodium particle on the hydroxide has been supplanted by the Hydrogen particle. The response is additionally a balance on the grounds that $HCl$ is an acid, and $NaOH$ sodium hydroxide is a base.
$NaOH\left( {aq} \right) + HCl\left( {aq} \right) \to NaCl\left( {aq} \right) + {H_2}O\left( l \right)$

Additional information:
In wastewater treatment, substance balance strategies are regularly applied to decrease the harm that an emanation may cause upon delivery to the climate. For pH control, well known synthetic substances incorporate calcium carbonate, calcium oxide, magnesium hydroxide, and sodium bicarbonate. The choice of a proper balance substance relies upon the specific application.
There are numerous employment of balance responses that are corrosive antacid responses. A typical use is acid neutralizer tablets. These are intended to neutralize overabundant gastric acid in the stomach ($HCl$ ) that might be causing distress in the stomach or lower throat. This can likewise be cured by the ingestion of sodium bicarbonate. Sodium bicarbonate is likewise usually used to neutralize corrosive spills in research centers, just as corrosive consumes.

Note:
We need to know that the chemical titration strategies are utilized for breaking down acids or bases to decide the obscure fixation. Either a pH meter or a pH marker which shows the place of balance by a particular shading change can be utilized. Straightforward stoichiometric computations with the known volume of the obscure and the known volume and molarity of the additional substance gives the molarity of the obscure.