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Question: Write the name of the following compounds: \({\text{A}}{{\text{l}}_{\text{2}}}{{\text{(S}}{{\text{...

Write the name of the following compounds:
Al2(SO4)3{\text{A}}{{\text{l}}_{\text{2}}}{{\text{(S}}{{\text{O}}_{\text{4}}}{\text{)}}_{\text{3}}}
NH4OH{\text{N}}{{\text{H}}_{\text{4}}}{\text{OH}}

Explanation

Solution

. Symbolically Aluminium is denoted as ‘Al{\text{Al}}’, Sulphur is denoted as ‘S{\text{S}}’, Oxygen is denoted as ‘O{\text{O}}’, Nitrogen is denoted as ‘N{\text{N}}’ and Hydrogen is denoted as ‘H{\text{H}}’. And by knowing the functional group and ion present in the compound we can name them.

Complete step by step answer: Name of the first compound Al2(SO4)3{\text{A}}{{\text{l}}_{\text{2}}}{{\text{(S}}{{\text{O}}_{\text{4}}}{\text{)}}_{\text{3}}} is ‘Aluminium sulphate’ as in this compound Aluminium metal and sulphate ion is present.
-Aluminium is present in the form of cation and showing +3 + 3 oxidation state, because atomic number of aluminium is 1313 and in its outermost shell 33electrons are present. By removing these three electrons aluminium gets stable electronic configuration, that’s why it shows +3 + 3 oxidation state.
-Sulphate is present in the form of anion and shows 2 - 2 oxidation state.
Name of the second compound NH4OH{\text{N}}{{\text{H}}_{\text{4}}}{\text{OH}} is ‘Ammonium Hydroxide’ as in this compound ammonium and hydroxide ions are present.
-Ammonium is present in the form of cation whose oxidation state is +1 + 1.
-Hydroxide is present in the form of anion whose oxidation state is 1 - 1.

Additional information: Both Aluminium sulphate and Ammonium hydroxide is basic in nature.
- Aluminium sulphate is also known by the name alum and used for the purification of water through the coagulation of impurities present in water.
-Ammonium hydroxide is mainly used as a cleaning agent in many factories, industries and houses.

Note: During the nomenclature of NH4OH{\text{N}}{{\text{H}}_{\text{4}}}{\text{OH}}, some of you may write ammonia in place of ammonium and that will be wrong. So always keep in mind that whenever NH4{\text{N}}{{\text{H}}_{\text{4}}} is given then we will use ammonium.