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Question

Mathematics Question on Sequences and Series

Write the first five terms of each of the sequences in Exercises 1 to 6 whose nth terms are: an = n n2 + 54\frac{5}{4}.

Answer

Substituting n = 1, 2, 3, 4, 5, we obtain

a1 = 1.12+54=64=32\frac{5}{4}=\frac{6}{4}=\frac{3}{2}

a2 = 2.22+54=2.94=92\frac{5}{4}=\frac{2.9}{4}=\frac{9}{2}

a3 = 3.32+54=3.144=212\frac{5}{4}=\frac{3.14}{4}=\frac{21}{2}

a4 = 4.42+54\frac{5}{4} = 21

a5 = 5.52+54=5.304=752\frac{5}{4}=\frac{5.30}{4}=\frac{75}{2}

Therefore, the required terms are 32,92,212,21,and752.\frac{3}{2},\frac{9}{2},\frac{21}{2},21,and\frac{75}{2}.