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Question

Mathematics Question on Sequences and Series

Write the first five terms of each of the sequences in Exercises 1 to 6 whose nth terms are: an = 36\frac{3}{6}

Answer

Substituting n = 1, 2, 3, 4, 5, we obtain

a1 = 2×1-36=16\frac{3}{6} =\frac{-1}{6}

a2 = 2×2-36=16\frac{3}{6} = \frac{1}{6}

a3 = 2×3-36=36=12\frac{3}{6} = \frac{3}{6} = \frac{1}{2}

a4 = 2×4-36=56\frac{3}{6} = \frac{5}{6}

a5 = 2×5-36=76\frac{3}{6} = \frac{7}{6}

Therefore, the required terms are 16,16,12,56,and76\frac{-1}{6}, \frac{1}{6},\frac{1}{2}, \frac{5}{6}, and \frac{7}{6}