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Chemistry Question on Law Of Chemical Equilibrium And Equilibrium Constant

Write the expression for the equilibrium constant, Kc for each of the following reactions:

  1. 2NOCl(g)⇋2NO(g)+Cl2(g)2NOCl (g) ⇋ 2NO (g) + Cl_2 (g)
  2. 2Cu(NO3)2(s)⇋2CuO(s)+4NO2(g)+O2(g)2Cu(NO_3)_2 (s) ⇋ 2CuO (s) + 4NO_2 (g) + O_2 (g)
  3. CH3COOC2H5(aq)+H2O(l)⇋CH3COOH(aq)+C2H5OH(aq)CH_3COOC_2H_5(aq) + H_2O(l) ⇋ CH_3COOH (aq) + C_2H_5OH (aq)
  4. Fe3+(aq)+3OH–(aq)⇋Fe(OH)3(s)Fe^{3+} (aq) + 3OH^– (aq) ⇋ Fe(OH)_3 (s)
  5. I2(s)+5F2⇋2IF5I_2 (s) + 5F_2 ⇋ 2IF_5
Answer

(i) Kc=[NO(g)]2[Cl2(g)][NOCl(g)]2K_c = \frac {[NO(g)]^2 [Cl_2(g)] }{[NOCl(g)]^2}

(ii) Kc=[CuO(s)]2[NO2(g)]4[O2(g)][Cu(NO3)2(g)]2K_c = \frac {[CuO(s)]^2 [NO_2(g)]^4 [O_2(g)]}{[Cu(NO_3)_2(g)]^2 }

=[NO2(g)]4[O2(g)]= [NO_2(g)]^4 [O_2(g)]

(iii) Kc=[CH3COOH(aq)][C2H5OH(aq)][CH3COOC2H5(aq)][H2O(l)]K_c = \frac {[CH_3COOH(aq)] [C_2H_5OH(aq)]}{[CH_3COOC_2H_5(aq)] [H_2O(l)]}

=[CH3COOH(aq)][C2H5OH(aq)][CH3COOC2H5(aq)]= \frac {[CH_3COOH(aq)] [C_2H_5OH(aq)]}{[CH_3COOC_2H_5(aq)]}

(iv) Kc=[Fe(OH)3(s)][Fe3+(aq)][OH−(aq)]3K_c =\frac {[Fe(OH)_3(s)]}{[Fe^{3+} (aq)] [OH^- (aq)]^3}

=1[Fe3+(aq)][OH−(aq)]3= \frac {1}{ [Fe^{3+} (aq)] [OH^-(aq)]^3}

(v) Kc=[IF5]2[I2(s)][F2]5Kc = \frac {[IF_5]^2}{[I_2(s)] [F_2]^5}

=[IF5]2[F2]5= \frac {[IF_5]^2}{[F_2]^5}