Question

Write the equation for the laboratory preparation of lead sulphate from lead nitrate using sulfuric acid.

Answer 1

To write the equation for the laboratory preparation of any component, we need to know the proportions we are mixing to form the same. The proportions will make up the stoichiometric coefficients which in return will form a balanced chemical equation.

Complete step-by-step answer: Let us first look into the involved components before describing the equation;
Lead nitrate-
It is a colourless powder which is soluble in water having chemical formula as $Pb{{\left( N{{O}_{3}} \right)}_{2}}$ .
Sulfuric acid-
This is a mineral acid composed of sulphur, oxygen and hydrogen with a molecular formula as ${{H}_{2}}S{{O}_{4}}$ .
Lead sulphate-
It is a white solid which exists in microcrystalline form; often seen in electrodes of car batteries. It has a chemical formula as $PbS{{O}_{4}}$ .
Now, as asked in the given problem statement;
We need to prepare lead sulphate from lead nitrate using sulfuric acid as;
$Pb{{\left( N{{O}_{3}} \right)}_{2}}+{{H}_{2}}S{{O}_{4}}\left( dil. \right)\to PbS{{O}_{4}}+2HN{{O}_{3}}$
We can see, for the required preparation we need to add dilute sulfuric acid to the medium and we get the nitric acid as the by-product in this reaction which has many applications in chemical industries.

Note: Do note to balance the equation as this is only the way to describe a process and the variations taking place. Also, the balanced chemical equation can help us extract much information about by-products along with the main product.