Question

Write the chemical names of the following compound:
${(C{H_3}COO)_2}Pb$

Answer 1

We know that in organic chemistry, the chemical formula provides us a way to represent any chemical substance using the symbol of the elements present in it. The molecular formula for the compound acetate is $C{H^3}CO{O^ - }$ and ‘Pb’ is lead.

Complete answer:
$C{H^3}CO{O^ - }$ is the acetate ion which means it has a negative charge of $\; - 1$. This ion is very common, for instance vinegar is, for the most part, acetic acid CH3COOH. This means that the negative charge of -1 has been filled with a hydrogen proton, charge of $+ 1$.
And Pb stands for the element ‘Lead’. Since. there are two oxidation state of Pb i.e. $+ 2$ and $+ 4$ then the only way for the total charge of the compound to be zero is:
$\Rightarrow Pb\left( { + 2} \right) + 2acetate\left( { - 1} \right) = 2 + \left( { - 2} \right) = 0$
Hence, the oxidation state of the lead is $+ 2$ here.
So, the name of the compound ${(C{H_3}COO)_2}Pb$ is known as lead (II) acetate or commonly known as lead acetate and it is a type of sweet, white powder that is crystal-like. It is also soluble in both water and glycerine.

Therefore, the chemical name of the compound ${(C{H_3}COO)_2}Pb$ is Lead(II) acetate.

Note:
It should be noted that the other name of Lead(II) acetate ($Pb{\left( {C{H_3}COO} \right)_2}$), are also lead acetate, lead diacetate, plumbous acetate, sugar of lead, lead sugar, salt of Saturn, lead salt, or Goulard's powder. Lead(II) acetate is used as a reagent to make other lead compounds and also as a fixative for some dyes. In low concentrations, it is the principal active ingredient in progressive types of hair colouring dyes.