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Question: Write relation between g and G....

Write relation between g and G.

Explanation

Solution

Hint: G is the force between two bodies of unit mass separated by distance r. G is known as a universal gravitational constant. g is the acceleration produced in a body falling under the action of gravitational pull of the earth. Here g is called acceleration due to gravity. Equation for g is F=mgF=mg and Equation for G is F=Gm1mr2F=G\dfrac{{{m}_{1}}m}{{{r}^{2}}}.

Complete step by step answer:
The gravitational force between two masses m1 and m2 is proportional to the product of mass and is inversely proportional to square of the distance (r) apart,
Fm1m2r2 F=Gm1m2r2 \begin{aligned} & F\propto \dfrac{{{m}_{1}}{{m}_{2}}}{{{r}^{2}}} \\\ & F=G\dfrac{{{m}_{1}}{{m}_{2}}}{{{r}^{2}}} \\\ \end{aligned}
Gravity – the force of attraction exerted by the earth on other objects is called gravity. The direction of force F is towards the center of the earth which is called the vertically downward direction force. This force is also called gravitational force and given as -
F=mgF=mg
Let m be the mass of an object and m1 be the mass of earth. And r is the radius of the earth.
F=Gm1mr2 mg=Gm1mr2 g=Gm1r2 \begin{aligned} & F=G\dfrac{{{m}_{1}}m}{{{r}^{2}}} \\\ & mg=G\dfrac{{{m}_{1}}m}{{{r}^{2}}} \\\ & g=G\dfrac{{{m}_{1}}}{{{r}^{2}}} \\\ \end{aligned}
The term Gm1r2G\dfrac{{{m}_{1}}}{{{r}^{2}}}is called acceleration due to gravity and is denoted by the letter g.
Hence relation between g and G is g=Gm1r2g=G\dfrac{{{m}_{1}}}{{{r}^{2}}}

Note: Students should remember that g is much different from G.
The value of g is g=9.8m/s2g=9.8m/{{s}^{2}} or for simplicity we useg=10m/s2g=10m/{{s}^{2}}.
And the value of G is so small and becomes appreciable only if two bodies have large masses. And approximately equal to 6.674×1011Nm2/kg26.674\times {{10}^{-11}}N{{m}^{2}}/k{{g}^{2}}