Question

Write Lewis dot symbols for atoms of the following elements: Mg, Na, B, O, N, Br.

Answer 1

$\text{Mg}$ : There are two valence electrons in $\text{Mg}$ atom.
⇒ Hence, the Lewis dot symbol for $\text{Mg}$ is:

$\text{Na}$ : There is only one valence electron in an atom of sodium.
⇒ Hence, the Lewis dot structure is:

$\text{B}$: There are 3 valence electrons in Boron atom.
⇒ Hence, the Lewis dot structure is:

$\text{O}$ There are six valence electrons in an atom of oxygen.
⇒ Hence, the Lewis dot structure is:

$\text{N}$: There are five valence electrons in an atom of nitrogen.
⇒ Hence, the Lewis dot structure is:

$\text{Br}$: There are seven valence electrons in bromine.
⇒ Hence, the Lewis dot structure is: