Question
Question: Write IUPAC name of the following compound:  , amino group (−NH2) and an alcohol or hydroxyl group (−OH) .
The priority order of various function groups is given as follows:
(−COOH)>(−SO3H)>(−COOR)>(−COCl)>(−CONH2)>(−CN)>(HC=O)>(−CO)>(−OH)>(−NH2)
Hence the carboxylic acid will be assigned the first position. The numbering will be done in a clockwise manner to assign the lowest possible positions. Therefore the second position will be occupied by the amino group and the fourth position will be occupied by the hydroxyl group.
Since (−COOH) group has the highest priority, the compound will be named benzoic acid or systematically named benzenecarboxylic acid. On alphabetically naming the remaining functional groups we get 2-amino,4-hydroxy benzenecarboxylic acid.
Thus the IUPAC name of the given compound is 2-amino,4-hydroxy benzenecarboxylic acid.
Note:
Once the first priority is assigned to a particular functional group like carboxylic acid in this case, then the numbering of the remaining functional groups is done relative to that of the prior group and not according to the functional group priority order.