Question
Question: Write \(\cos 20^\circ \) in terms of \(\sin \)?...
Write cos20∘ in terms of sin?
Solution
Hint : Here, in the given question we need to write cos20∘ in terms of sine. cosine and sine are cofunctions. Cofunction is a trigonometric function whose value for the complement of an angle is equal to the value of a given trigonometric function of the angle itself. So, as we know that sine and cosine are complementary angles. Two angles are said to be complementary, if their sum is 90∘. For example: θ and (90∘−θ) are complementary angles for an acute angle θ because their sum is 90∘. Similarly sine and cosine are complementary angles. Therefore, cos of an angle = sin of its complementary angle. We can write it as: cosθ=sin(90∘−θ). So, we will write cos20∘ as sin(90∘−20∘), and proceed.
Complete step-by-step answer :
Given, cos20∘
As we know cosθ=sin(90∘−θ). Therefore, the above written function can be written in terms of sine as:
⇒cos20∘=sin(90∘−20∘)
On subtracting the terms inside the bracket, we get
⇒cos20∘=sin(70∘)
Hence, the value of cos20∘ in terms of sine is sin70∘.
So, the correct answer is “sin70∘”.
Note : Remember that conjunctions are pairs of trigonometric functions. Remember a simple relationship: sin(α)=cos(β) where α+β=90∘. This also holds true for cosec and sec, and tan and cot. Here, in the given question, we wrote cos20∘ in terms of sine, as you can see cos20∘ is a very small angle that is why we used cosθ=sin(90∘−θ) formula, as know (90∘−θ) lies in the first quadrant and in first quadrant all the trigonometric ratios are positive. While writing one trigonometric ratio in terms of another trigonometric ratio, one must remember in which quadrant sign is positive or negative for that particular trigonometric function.