Question
Question: Write chemical equations for the following reactions: \({\rm I})\) Reaction between gallium \(({\r...
Write chemical equations for the following reactions:
I) Reaction between gallium (III) oxide and dilute nitric acid to form salt and water only.
II) Reaction between gallium (III) oxide and sodium hydroxide solution forms only water and a salt containing the negative ion Ga2O42−
Solution
Find out the charge on Gallium in the given reactants. Both the reactions are displacement reactions so the Oxygen in gallium (III) oxide is replaced by another element from the second reactant. One of the products is already given as water so the salt can be found accordingly.
Complete answer:
I) In this reaction, gallium (III) oxide and dilute nitric acid are given to us as reactants and the products are a salt and water. If we consider the unknown salt to be X then the equation would be
Ga2O3+HNO3→X+H2O
Now, from this equation we know that the charge on Gallium is +3 and hence we can conclude that X is Ga(NO3)3 and the equation would be
Ga2O3+HNO3→Ga(NO3)3+H2O
Balancing the equation:
Ga2O3+6HNO3→2Ga(NO3)3+3H2O
II) The reactants given to us are Ga2O3 and NaOH and the products are water and a salt containing Ga2O42− , let us consider the unknown salt to be X
Ga2O3+NaOH→X+H2O
From the given information we can say that the salt is Na2Ga2O4 since it is a displacement reaction.
The equation would become Ga2O3+NaOH→Na2Ga2O4+H2O
Balanced equation is given as Ga2O3+2NaOH→2NaGaO2+H2O
Additional Information:
Gallium (III) trioxide is an inorganic compound with the formula Ga2O3 . It is an amphoteric substance and also dissolves in strong alkali. It is studied in the use of phosphors, lasers, luminescent materials etc.
Note:
The charge on gallium in the given reactants is three. Hence during the displacement reaction, the three oxygen atoms attached to gallium are replaced with the ions of other given reactant molecules forming water molecules and a salt as products.