Question

Write balanced equation for:
(i) $B{F_3} + LiH \to$
(ii) ${B_2}{H_6} + {H_2}O \to$
(iii) $NaH + {B_2}{H_6} \to$
(iv) ${H_3}B{O_3}\xrightarrow{\Delta }$
(v) $Al + NaOH \to$
(vi) ${B_2}{H_6} + N{H_3} \to$

Answer 1

A chemical reaction is represented in the form of chemical equation. The balanced term is used to specify the equality of the number of reactants and product in a reaction.

Complete step by step answer: A balanced chemical reaction is referred to as an equation which contains equal numbers of each type of atoms present on the reactant side as well as on the product side.
The elemental or symbolic representation of a chemical reaction is called a chemical equation. The balanced equation is one in which the number of atoms or substances is equal on both sides of the equation. The reactants are chemicals written on the left-hand side of an equation and the product are chemicals written on the right-hand side.
According to this law, mass can neither be created nor be destroyed in a chemical reaction, so the number of atoms which are present in the reactants must balance the number of atoms which are present in the products. Hence, if the law of conservation of mass is not applicable for a reaction the chemical equation is not balanced.
The balanced equations for the given reaction are as follows:
(i) $2B{F_3} + 6LiH \to {B_2}{H_6} + 6LiF$
In this reaction boron trifluoride and lithium hydride reactions react to produce diborane and lithium fluoride. The reaction is carried out at $450K$.
(ii) ${B_2}{H_6} + 6{H_2}O \to 2{H_3}B{O_3} + 6{H_2}$
The diborane reacts with water molecules to produce orthoboric acid and hydrogen gas.
(iii) $2NaH + {B_2}{H_6} \to 2NaB{H_4}$
The sodium hydride reacts with diborane to produce sodium borohydride.
(iv) ${H_{3}}B{O_3}\xrightarrow{\Delta }HB{O_2} + {H_{2}}O$
$4HB{O_2}\xrightarrow[{ - {H_{2}}O}]{\Delta }{H_2}{B_4}{O_7}\xrightarrow[{ - {H_{2}}O}]{\Delta }2{B_2}{O_3}$
The thermal decomposition of boric acid leads to formation of metaboric acid. The decomposition does not stop at this stage and is continued to the formation of boron trioxide.
(v) $Al + 3NaOH \to Al{(OH)_3} + 3Na$
The activated aluminium metal undergoes reaction with sodium hydroxide to produce aluminium hydroxide and metallic sodium.
(vi) $3{B_2}{H_6} + 6N{H_3} \to 2{B_3}{N_3}{H_6} + 12{H_2}$
The diborane undergoes reaction with ammonia to generate borazine and hydrogen gas.

Note:
The number written before the reactants are called reactant coefficients and that of product are called product coefficients. A balanced chemical equation gives information about the relative formation of the products.