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Question: Write an equation of the slope intercept form of the line passing through the points (2,3) and (4.6)...

Write an equation of the slope intercept form of the line passing through the points (2,3) and (4.6).

Explanation

Solution

Hint: In the above given question, use the given points to find the slope of the equation and also find the y-intercept. Both these values so obtained can be substituted in the slope-intercept equation which is the m=6342m = \dfrac{{6 - 3}}{{4 - 2}}required solution.
We know that the slope of line passing through two points(x1,y1)\left( {{x_1},{y_1}} \right)and(x2,y2)\left( {{x_2},{y_2}} \right)is
m=y2y1x2x1m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} … (1)(4,6)\left( {4,6} \right)
So, the slope of the line passing through the points(2,3)\left( {2,3} \right)and can be obtained by using m=32\therefore m = \dfrac{3}{2}equation (1),

Complete step-by-step answer:
Therefore, the slope of the line is32.\dfrac{3}{2}.
Now use the slope and point (2,3) to find the y-intercept.
We know that
y=mx+by = mx + b … (2)
Therefore, after substituting the values in the equation (2), we get,
3=(32×2)+b\Rightarrow 3 = \left( {\dfrac{3}{2} \times 2} \right) + b
3=3+b\Rightarrow 3 = 3 + b
b=33\Rightarrow b = 3 - 3
b=0\therefore b = 0
Now, after substituting the values of the slope and the intercept in the slope-intercept form, we get the equation as,
y=mx+by = mx + b
y=32x+0\Rightarrow y = \dfrac{3}{2}x + 0
y=32x\Rightarrow y = \dfrac{3}{2}x
Hence, the equation of the line isy=32x.y = \dfrac{3}{2}x.

Note: In order to solve the above given question, an adequate knowledge about lines and equations is required. Various equations like equation of slope, y-intercept, slope- intercept must be known. After substituting the given values in these equations, the required answer can be obtained.