Question
Question: Work for the following process ABCD on a monoatomic gas is : <img src="https://cdn.pureessence.tec...
Work for the following process ABCD on a monoatomic gas
is :
A
w = – 2 P0 V0ln 2,
B
w = – 2 P0 V0ln 2
C
w = – P0 V0 (1+ ln 2)
D
w = – P0 V0ln 2,
Answer
w = – 2 P0 V0ln 2,
Explanation
Solution
At A and D the temperatures of the gas will be equal, so
DE = 0,
DH = 0
Now w = wAB + wBC + wCD = – P0 V0 – 2P0 V0 ln 2 + P0 V0 = – 2P0 V0 ln 2