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Question

Physics Question on Magnetic Force

Work done in turning a magnet of magnetic moment M by an angle of 90? from the mgnetic meridian is n times the corresponding work done to turn through an angle of 60?, where n is

A

01-Feb

B

2

C

01-Apr

D

1

Answer

2

Explanation

Solution

W1 = - MB (cos 90? - cos 0?) = MB
W2 = - MB (cos 60? - cos 0?)
= -MB(121)=12\left(\frac{1}{2}-1\right)=\frac{1}{2} MB
Which is =12=\frac{1}{2} W1
As, W1 = n W2 \quad\quad ? n = 2