Solveeit Logo
Login

Question

Physics Question on electrostatic potential and capacitance

Work done in placing a charge of 8×10−18C8\times 10^{-18}C on a condenser of capacity 100 μ F100 \, \mu \, F is

A

16×10−32J16\times 10^{-32}J

B

31×10−26J31\times 10^{-26}J

C

4×10−10J4\times 10^{-10}J

D

32×10−32J32\times 10^{-32}J

Answer

32×10−32J32\times 10^{-32}J

Explanation

Solution

Here, q=8×10−18Cq=8 \times 10^{-18} C, C=100 μF=10−4FC=100\, \mu F =10^{-4} F V=qC=8×10−1810−4V =\frac{q}{C}=\frac{8 \times 10^{-18}}{10^{-4}} =8×10−14volt=8 \times 10^{-14} volt Work done =12qV=\frac{1}{2} q V =12×8×10−18×8×10−14=\frac{1}{2} \times 8 \times 10^{-18} \times 8 \times 10^{-14} =32×10−32J=32 \times 10^{-32} J