Question
Question: Work done in converting one gram of ice at – 10<sup>0</sup>*C* into steam at 100<sup>0</sup>*C* is...
Work done in converting one gram of ice at – 100C into steam at 1000C is
A
3045 J
B
6056 J
C
721 J
D
616 J
Answer
3045 J
Explanation
Solution
Work done in converting 1gm of ice at – 100C to steam at 1000C
= Heat supplied to raise temperature of 1gm of ice from – 100C to 00C [m × cice × ∆T]
+ Heat supplied to convert 1 gm ice into water at 00C [m × Lice]
+ Heat supplied to raise temperature of 1gm of water from 00C to 1000C [m × cwater × ∆T]
+ Heat supplied to convert 1 gm water into steam at 1000C [m × Lvapour]
= [m × cice × ∆T] + [m × Lice] + [m × cwater × ∆T] + [m × Lvapour]
= [1×0.5×10]+[1×80]+[1×1×100]+[1×540] = 725calorie=725×4.2=3045J