Solveeit Logo
Login

Question

Question: Work done during isothermal expansion of one mole of an ideal gas from 10 atm to 1 atm at 300 K is (...

Work done during isothermal expansion of one mole of an ideal gas from 10 atm to 1 atm at 300 K is (Gas constant = 2).

A

938.8 cal.

B

1138.8 cal.

C

1381.8 cal.

D

1581.8 cal.

Answer

1381.8 cal.

Explanation

Solution

373K373Klog ΔHvap=37.3kJmol−1\Delta H_{vap} = 37.3kJmol^{- 1}

111.9Jmol−1K−1111.9Jmol^{- 1}K^{- 1}log 37.3Jmol−1K−137.3Jmol^{- 1}K^{- 1} 100Jmol−1K−1100Jmol^{- 1}K^{- 1}