Question

Work done by 0.1 mole of a gas at $27^{o}C$ to double its volume at constant pressure is (R = 2 cal mol^{–1 o}C^–1)

• A. 54 cal
• B. 600 cal
• C. 60 cal
• D. 546 cal

Answer 1

Answer: (C)

60 cal

Answer 2

$W = P\Delta V = nR\Delta T = 0.1 \times 2 \times 300 = 60\mspace{6mu} cal$